Advanced Placement (AP), 01.10.2019 02:00 zaiah329

The change in the amino acid sequence illustrated in figure 1 caused a change in the shape of receptor x. based on the r groups of the original and substituted amino acids, explain why receptor x changed shape

The change in the amino acid sequence illustrated in figure 1 caused a change in the shape of recept

Answers: 2

Show answers

Answers

Answer from: Quest

answer; (d); skeletal muscles and sensory receptors;

Answer from: Quest

Sixth step is a solution implemented in the decision-making process of solving a workplace problem

Answer from: Quest

They are both unlikely. certain would be 100%, likely would be anywhere above 50%, and unlikely would be under 50%can i have brainliest, ?

Answer from: Quest

Answer: the interval on which the curve is concave up is (-∞, -1/2)====== $\displaystyle y = \int_{0}^x \frac{1}{1 + t + t^2} \; dt$ we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \end{aligned}$ let the function f denote be the anti-derivative of the inside expression, i.e. a function such that $(d/dx)f(x) = 1/(1 + t + t^2)$ .then use the fundamental theorem of calculus: $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \\& = \frac{d}{dx} \big[ f(x) - f(0) \big] & & \text{\footnotesize apply ftc} \\ & = \frac{d}{dx}f(x) - 0 \\ & = \frac{1}{x + x + x^2} & & \text{\footnotesize since $\frac{d}{dx}f(x) = \frac{1}{1 + x + x^2}$ } \end{aligned}$ differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function $\begin{aligned} \frac{d}{dx} \left( \frac{dy}{dx} \right) & = \frac{d}{dx}\left(\frac{1}{1 + x + x^2} \right) \\ \frac{d^2y}{dx^2} & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot \tfrac{d}{dx}(1 + x + x^2) \\ & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot (1 + 2x) \\ & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \end{aligned}$ find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x $\begin{aligned} 0 & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \\ 0 & = -(1+2x) \\ -1 & = 2x \\ x & = -1/2 \end{aligned}$ where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation 1 + x + x² = 0results in a discriminant of $b^2 - 4ac = 1^2 - 4(1)(1) = -3$ meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = -1} & = \frac{-(1+2(-1))}{\left(1+(-1)+(-1)^2\right)^2} \\ & = \frac{-(1-2)}{1} \\ & = 1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = 0} & = \frac{-(1+2(0))}{\left(1+(0)+(0)^2\right)^2} \\ & = \frac{-(1)}{1} \\ & = -1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is (-∞, -1/2)

Another question on Advanced Placement (AP)

Advanced Placement (AP), 23.06.2019 08:10

Free points + brainliest! answer this correctly and you shall receive! to obtain a class e license, you don’t need to a. be at least 16 years old b. complete a tlsae course c. pass the driving skills test d. be a u.s. citizen

Answers: 1

Answer

Advanced Placement (AP), 23.06.2019 22:00

Amedical center’s rectangular parking lot currently has a length of 30 meters and a width of 20 meters. the center plans to expand both the length and the width of the parking lot by 2x meters. what polynomial in standard form represents the area of the expanded parking lot?

Answers: 2

Answer

Advanced Placement (AP), 24.06.2019 12:30

States might choose to cooperate at the regional or global level for all of the following reasons except (2 points) a.) to gain regional political influence b.) to engage in dispute resolution c.) to assure basic human rights d.) to encourage economic interaction e.) to increase national sovereignty

Answers: 3

Answer

Advanced Placement (AP), 26.06.2019 04:30

Free 99 pts answer before ! i'm just bored

Answers: 2

Answer

You know the right answer?

The change in the amino acid sequence illustrated in figure 1 caused a change in the shape of recept...

Questions