Two identical spheres are released from a device at time t = 0 from the same height H, as shown above. Sphere A has no initial velocity and falls straight down. Sphere B is given an initial horizontal velocity of magnitude v0 and travels a horizontal distance D before it reaches the ground. The spheres reach the ground at the same time t f , even though sphere B has more distance to cover before landing. Air resistance is negligible.

  The spheres reach the ground at the same time (true)

Explanation:

The acceleration in the vertical direction is the same for both spheres, so the distance they cover in a given time is the same. The additional (horizontal) distance covered by sphere B is facilitated by its horizontal velocity.

True: the spheres reach the ground at the same time.

ek = (m·v2) / 2

v - velocity of system after the collision

m = m1 + m2

ek = (m1 + m2) ·v2/2

ek = (200 + 250) ·2,32/2 = 450·5,29/2 = 1190,25 j

answerthe above statement is (true);