Advanced Placement (AP), 28.09.2020 01:01 mgendin
I got 8x/3cubroot of (1+8x). Is this right can someone explain the steps that they did to get the answer?
Answers: 2
![\frac{dy}{dx}[\sqrt[3]{1+8x} ] = \frac{8}{3\sqrt[3]{(1+8x)^2} }](/tpl/images/0782/0591/73ad6.png)
and 
. Let's find them.![f'(x)= \frac{d}{du} [\sqrt[3]{u} ] = \frac{d}{du} [u^\frac{1}{3} ] = \frac{1}{3}u^\frac{-2}{3} = \frac{u^\frac{-2}{3} }{3} = \frac{1}{3u^\frac{2}{3} } \\g'(x)= \frac{d}{dx} [1+8x] = 8](/tpl/images/0782/0591/80bb1.png)
function and put it into ![(\frac{1}{3(1+8x)^\frac{2}{3} } )(\frac{8}{1} ) = \frac{8}{3(1+8x)^\frac{2}{3} } = \frac{8}{3\sqrt[3]{(1+8x)^2} }](/tpl/images/0782/0591/62f55.png)
![\frac{8}{3\sqrt[3]{(1+8x)^2} }](/tpl/images/0782/0591/57a7d.png)
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I got 8x/3cubroot of (1+8x). Is this right can someone explain the steps that they did to get the an...
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