8. In a recent survey of 1002 people, 701 said that they voted in a recent presidential election. Voting records show that 61% of eligible voters actually did vote.
a) Find the 95% confidence interval estimate of the proportion of people who say that they voted.
b) Are the survey results consistent with the actual voter turnout of 61%? Why or why not?
c) How would the confidence interval change if we increased the confidence level to 99%? Find
the 99% confidence interval estimate to support your answer.

That is super long dude

The answer is    (d) 7/2======we have    we also  have an integral      notice how function f splits up at x = 0. there's a left piece and a right pieceso we'll need to do the same thing with our integral: split it at x = 0we use a property of integrals that allows us to split up and sum:     notice that for the piecewise function f, the function has the equationf(x) = x when x  ≤ 0. so for the integral  , f(x) = x so it changes into      for the piecewise function f, the function has the equationf(x) = x+1  when x  > 0. for the integral  , we have    therefore, back to our splitted integral: