A car moving at 15 m/s skids to a stop in 20m. If the car travels at 30 m/s, how far will it skid, assuming the same constant braking force?

If the car travels at 30 m/s, the car will skid 80 m

Determination of the deceleration of the car Initial velocity (u) = 15 m/sFinal velocity (v) = 0 m/sDistance (s) = 20 mDeceleration (a) =?

v² = u² + 2as

0² = 15² + (2 × a × 20

0 = 225 + 40a

Collect like terms

0 – 235 = 40a

–225 = 40a

Divide both side 40

a = –225 / 50

a = –5.625 m/s²

Determination of the distanceDeceleration (a) = –5.625 m/s²Initial velocity (u) = 30 m/sFinal velocity (v) = 0 m/sDistance (s) =?

v² = u² + 2as

0² = 30² +(2 × –5.625 × s)

0 = 900 – 11.25s

Collect like terms

0 – 900 = –11.25s

–900 = –11.25s

Divide both side by –11.25

s = –900 / –11.25

s = 80 m

Therefore, the car will skid 80 m

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