Advanced Placement (AP), 27.05.2021 16:00 liloleliahx2

what form of agriculture is most common in somalia? intensive or extensive? subsistence or commercial?

Answers: 3

Show answers

Answers

Answer from: Quest

consider the following scenario, then describe how you might conduct a study using ansrs, convenience sample, and a voluntary response sample. you are interested in parents' opinion of the war in iraq. your population is parents of high school students. your question is, "do you believe that the war in

Answer from: Quest

Answer: the interval on which the curve is concave up is (-∞, -1/2)====== $\displaystyle y = \int_{0}^x \frac{1}{1 + t + t^2} \; dt$ we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \end{aligned}$ let the function f denote be the anti-derivative of the inside expression, i.e. a function such that $(d/dx)f(x) = 1/(1 + t + t^2)$ .then use the fundamental theorem of calculus: $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \\& = \frac{d}{dx} \big[ f(x) - f(0) \big] & & \text{\footnotesize apply ftc} \\ & = \frac{d}{dx}f(x) - 0 \\ & = \frac{1}{x + x + x^2} & & \text{\footnotesize since $\frac{d}{dx}f(x) = \frac{1}{1 + x + x^2}$ } \end{aligned}$ differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function $\begin{aligned} \frac{d}{dx} \left( \frac{dy}{dx} \right) & = \frac{d}{dx}\left(\frac{1}{1 + x + x^2} \right) \\ \frac{d^2y}{dx^2} & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot \tfrac{d}{dx}(1 + x + x^2) \\ & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot (1 + 2x) \\ & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \end{aligned}$ find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x $\begin{aligned} 0 & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \\ 0 & = -(1+2x) \\ -1 & = 2x \\ x & = -1/2 \end{aligned}$ where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation 1 + x + x² = 0results in a discriminant of $b^2 - 4ac = 1^2 - 4(1)(1) = -3$ meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = -1} & = \frac{-(1+2(-1))}{\left(1+(-1)+(-1)^2\right)^2} \\ & = \frac{-(1-2)}{1} \\ & = 1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = 0} & = \frac{-(1+2(0))}{\left(1+(0)+(0)^2\right)^2} \\ & = \frac{-(1)}{1} \\ & = -1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is (-∞, -1/2)

Answer from: Quest

mr sandman bring me an g make it the oogiest that ive ever seen

Lolololoololololollolololollolololollolo fu ce annysjfdwyifvwvfhwgvflivsferfw4fwfwefwe reason

Answer from: Quest

uh cause they want to stop talkin to you (depends if its online)

or if its in real life they just want you to sleep ig

or maybe they jus tired.

but if it's online they prob just saying that cause they dont wanna talk to you or they want u to leave

Another question on Advanced Placement (AP)

Advanced Placement (AP), 25.06.2019 19:30

How has nathan price adapted to his situation in the congo in the poisonwood bible?

Answers: 1

Answer

Advanced Placement (AP), 26.06.2019 01:00

In your own words define the following terms. 1 hibernation. 2 hormone. 3 behavior. 4 stimulus

Answers: 1

Answer

Advanced Placement (AP), 26.06.2019 08:00

Which of the following is a downside to using a professional naming firm? question options: you'll no longer have control over your company's name. most aren't very good at coming up with effective names and logos. you will need to be cautious about the firm stealing your business idea. most are fairly expensive, charging from $5,000 to $80,000 to develop a name.

Answers: 1

Answer

Advanced Placement (AP), 27.06.2019 01:30

Astitch in time saves nine. a penny saved is a penny earned. these sentences similar in meaning opposite in meaning neither the same nor the opposite

Answers: 1

Answer

You know the right answer?

what form of agriculture is most common in somalia? intensive or extensive? subsistence or commercia...

Questions