Advanced Placement (AP), 28.07.2019 22:30 allieballey0727

What is a certificate of incorporation? a. the taxes of a stockholder must pay if he or she sells ownership in a corporation b. a license to form a corporation issued by the state government c. the stocks representing a majority interest in a corporation d. an annual report filed by a corporation with the securities and exchange commission which of the following is one disadvantage of incorporation? a. limited liability for owners b. potential loss of control by founders c. transferable ownership d. long life name two countries that operate the world's largest multinationals today.

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Answer from: Senica

B. a license to form a corporation issued by the state government

B. potential loss of control by founders

United States of America and Japan

Explanation:

Incorporation is the formal process of registering a business such that the business becomes a separate entity from the owners of the business. On the successful registration/incorporation of a business by the promoters, the government issues a certificate known as the certificate of incorporation.

As such, a certificate of incorporation is a license to form a corporation issued by the state government. Option B

One disadvantage of incorporation is potential loss of control by founders. Other items such as limited liability for owners, transferable ownership and long life are advantages.

The United States of America and Japan operate the world's largest multinationals today.

Answer from: danni51

For the first question its B a certificate of incorporation is what legitimizes a corporation.
as for the seconded question the answer is B because you can lose control of a corporation to people that may not like what you are doing or something like that

Answer from: Quest

You need to figure out at which x-value does the graph has a tangent line slope of -1.remember, the derivative is the slope of the tangent line. so find the derivative function and set it to equal -1 to find the x-value that will have a tangent line slope of 0.differentiate with the chain rule. $\begin{aligned} f(x) & = (0.5)^{2x} \\ f'(x) & = 0.5^{2x} \cdot \ln(0.5) \cdot (2x)' \\ f'(x) & = 0.5^{2x} \cdot \ln(0.5) \cdot 2 \\ f'(x) & = 2\ln(0.5) \cdot 0.5^{2x} \end{aligned}$ set the derivative to equal -1 and solve for x. $\begin{aligned} -1 & = 2\ln(0.5) \cdot 0.5^{2x} \\ -\frac{1}{2} & = \ln(0.5) \cdot 0.5^{2x} \\ -\frac{1}{2\ln(0.5)} & = 0.5^{2x} \end{aligned}$ take log base 10 of both sides. also recall that $\log_c(m^n) = n \log_c m$ . $\begin{aligned} \log\left[ -\frac{1}{2\ln(0.5)}\right] & = \log\left[0.5^{2x}\right] \\ \log\left[ -\frac{1}{2\ln(0.5)}\right] & = 2x \log(0.5) \\ \dfrac{\log\left[ -\frac{1}{2\ln(0.5)}\right]}{2\log(0.5)} & = x \\ x & \approx 0.2356 \end{aligned}$ so the x-coord of the point of tangency is $x \approx 0.2356$ .the y-coordinate of this point of tangency can be calculated using the original function: $\begin{aligned} f(x) & = (0.5)^{2x} \\ f(0.2356) & = (0.5)^{2 \cdot 0.2356} \\ & \approx 0.7213 \end{aligned}$ using point-slope form, the equation of the tangent line is $y - 0.7213 = -1(x-0.2356)$ the x-intercept of this tangent line is when the graph is at y=0. $\begin{aligned} 0 - 0.7213 & = -1(x-0.2356)\\ - 0.7213 & = -(x-0.2356) \\ 0.7213 & = x-0.2356\\ x & = 0.9569 \end{aligned}$ this rounds off to $x & = 0.957$ .choice c.

Answer from: Quest

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