**80 points** answer! in a population, the dominant allele of a certain trait occurs  84% of  the time. a) what is the frequency of the recessive phenotype? b) what is the frequency of the dominant allele? c) what is the frequency of the heterozygote genotype?

So let's make p = dominant allele and q = recessive allele
p+q = 1, and (p+q)^2 = 1^2 thus
p^2 + 2pq + q^2 = 1, where p^2 = homozygous dominant, 2pq = heterozygous, and q^2 = homozygous recessive
So if p = .84, then q = 1-.84 = .16

a) recessive phenotype = q^2 = (.16)^2 = .0256
= 2.6%

b) dominant allele = p = .84 = 84%

c) heterozygous genotype = 2pq = 2(.84)(.16)
= .269 = 26.9%

Idon’t see any choices but i think it’s because it’s the work for that class and so the teacher doesn’t get confused