the length of a rectangle is 4 more than twice its width if the perimeter of the triangle is 106 what are the numerical values of the length and with

12 feet

Explanation:

Let the length and width of the rectangle be 2w + 4 and w.

Area of the rectangle is Length X Breadth i.e.,

(2w + 4) x w = 48

=> 2w^2 + 4w = 48

=> 2w^2 + 4w - 48 = 0

=> w^2 + 2w - 24 = 0

=> w^2 + 6w - 4w - 24 = 0

=> w(w+ 6) - 4(w + 6) = 0

=> (w - 4)(w + 6) = 0

=> w = 4, -6.

Negative value of w is inappropriate.

Hence, width w is 4 feet.

Length is 2 x 4 + 4 = 8 + 4 = 12 feet

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