Eukaryotic cells are 10-100 times the size of prokaryotic cells. how do eukaryotic cells resolve the surface area to volume limitations that favor smaller cells?

The surface area of a cell is approximated by the surface area of a sphere, given by the expression, 4πr². The volume of the spherical cell is given by the expression, 4πr³/3. The ratio between surface area and volume turn out to be, 1:r/3, or 3:r. This indicates that the SA/volume ratio is inversely related to the radius of the cell. Greater the radius, lower the ratio. Higher ratios are present in the prokaryotic cells This enables them to exchange food and water from their environment by the simple process of osmosis and diffusion. Eukaryotes have a larger cell radius and size. Thus, eukaryotes find it harder to exchange food and water by simple diffusion, rather they have specialised organelle present in the cell that actively transport food and water into the cell. These specialised organelles help the cell avoid the problem due to small SA/volume ratio.

from the original order (top to bottom) the new order will go

1 (founder)

4 (hawk)

2 (mutate)

3 (next generation)

ecological efficiency: % of usable energy transferred as

biomass from one trophic level to the next typical is 10% efficient (90% of

energy is lost),is diagramed as the pyramid of energy flow. then osprey eagle

are tertiary consumer and the shrimp are primary consumer, so to balance

mass of shrimp (1/0.1) / 0.1 = 100 kg