An individual that is homozygous dominant for type b blood and little finger shape mates with an individual that is heterozygous for type a blood and homozygous recessive for little finger shape . what are the predicted genotypic and phenotypic ratios for the cross?

Let "L" be the dominant allele for little finger shape and "l" be the recessive allele for the same.

It is given that a person is homozygous dominant for blood group B and little finger shape. Hence, the genotype would be LL

The other person is heterozygous for blood group A and homozygous recessive for little finger shape. Hence, the genotype would be

The type of gametes formed by the first parent would be only.

The type of gametes formed by second parent would be and il.

The cross is shown in the attached figure.

According to the cross, we get two phenotype:

According to the cross, we get two genotype:

a

explanation:

many plants naturally reproduce this way, but it can also be induced artificially. horticulturalists have developed asexual propagation techniques that use vegetative plant parts to replicate plants. success rates and difficulty of propagation vary greatly. monocotyledons typically lack a vascular cambium and therefore are harder to propagate.