What are the number of protons, neutrons, and electrons for the −2 anion from the 17o isotope of oxygen? (the atomic number of oxygen is 8.) select one: a. 8p+; 8n; 6e− b. 8p+; 10n; 8e− c. 7p+; 10n; 10e− d. 8p+; 9n; 10e−

The correct answer is d. 8p+; 9n; 10e−

Oxygen exists in three isotopes ¹⁶O, ¹⁷O and ¹⁸O. The atomic number of oxygen is 8. It means its nuclei has 8 protons. The given is oxide⁻² anion. This means it has gained 2 electrons. Thus, oxide anion have 8 protons and 10 (8+2) electrons. The number of neutrons depends on the isotope, in this question mass number is given¹⁷O. The mass number is the sum of the protons and neutrons in the nucleus. Hence, number of neutrons oxide anion will be 17-8 = 9 neutrons.  

the oxygenated blood then leaves the lungs through pulmonary veins, which return it to the left heart, completing the pulmonary cycle. this blood then enters the left atrium, which pumps it through the mitral valve into the left ventricle. from the left ventricle, the blood passes through the aortic valve to the aorta.

deoxygenated blood leaves through the right ventricle through the pulmonary artery. from the right atrium, the blood is pumped through the tricuspid valve (or right atrioventricular valve), into the right ventricle.

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