If a cubical cell with with 2 cm sides doubles the dimensions of its sides what change occurs to the ratio of its surface area to volume

The surface area of a cell is  6 × side² and volume of a cubical cell is side³.

Surface area of  cell having side 2 cm = 6 × 2 × 2 = 24 cm²

volume of the cell = 2 ×2 × 2 = 8 cm³

Therefore, surface area to volume ration is 24÷8 = 3 : 1

If the side of a cell is doubled,  then

Surface area of cell = 6 × 4 × 4 = 96 cm²

volume of the cell = 4 × 4 × 4 = 64 cm³

Therefore, surface area to volume ration is 96 ÷ 64 = 3 : 2  

Surface area to volume ratio decreases.

events in order:

1.       vishnu schist

2. zoroaster granite

3. bass limestone

4. hakatar   shale

5. igneous intrusion

6. shinumo quartzite

7. dox sandstone

8. tapeats limestone

9. bright angel shale

10. muav limestone

11. temple butte limestone

12. redwall limestone  

nonconformity

answer: the unkar group shows angular unconformity because the layers are turned at angle.

unconformity

answer: specifically the angular unconformity occurs between the cambrian and precambrian rocks. the dox sandstone, shinumo quartzite, hakatar shale, and bass limestone have been filled. an angular unconformity occurs between the cambrian and precambrian rocks. the dox sandstone, shinumo quartzite, hakatar shale, and bass limestone have been filled.

disconformity

answer: the disconformities aremarked irregular lines between the sedimentaryrocks layers.