Cross a yyll {heterogeneous parent with dominant) with yyll (homologous parent with recessive traits). look at the number of phenotypes u of the f1 generation. yyll x yy (parents, crosses will give you these offspring: yyll: 400 yyll: 100 yyll: 100 yyl

P:              YyLl                  x             yyll

G:        YL    Yl   yL  yl       x                    yl

F1: YyLl, Yyll, yyLl, yyll

G= 1:1:1:1

F= 1:1:1:1

            YL                   Yl                  yL              yl

yl        YyLl                Yyll                yyLl            yyll

answer; i believe the correct answer is ( proteins );

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