In guinea pigs, black fur (b) is dominant over white fur (b). cross a heterozygous (hybrid) black guinea pig with a homozygous (purebred) white guinea pig. complete a punnett square, identify the genotype(s), phenotype(s), and probability (% and fraction) that the offspring will be black and white?

The heterozygous (hybrid) black guinea pig = Bb

Homozygous (purebred) white guinea pig = bb

When these two are crossed the resulting genotypes are

Bb x bb

= Bb, Bb, bb, bb

Bb = black & white phenotype

bb= white phenotype

So, the cross will result into

2 black and white phenotype out of four thus the probability = 2/4 = 50 %

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the correct answer is ( hypoglycemia ); good luck

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