In the previous question, you used the hardy-weinberg equation to determine the frequencies of the genotypes for hh, hh, and hh, given gene frequencies of h = 0.2 and h = 0.8. these frequencies were: hh = 0.04 hh = 0.32 hh = 0.64 now, determine the expected numbers of each organism in the population (total size = 150): number of hh = number of hh = number of hh =

If frequencies are: HH = 0.04 Hh = 0.32 hh = 0.64, this expressed in the percentage is 4%, 32% and 64%  (4+32+64=100) respectively. If the total number of organisms in population is 150 then:  

Number of organisms with HH genotype is 0.4*150= 6

Number of organisms with Hh genotype is 0.32*150=48

Number of organisms with hh genotype is 0.64*150=96

6+48+96=150

a. suckling by young

b. hypothalamus

c. dopamine

d. trh

e. anterior pituitary

f. mammary glands

g. milk production