Life as we know it depends on the genetic code: a set of codons, each made up of three bases in a dna sequence and corresponding mrna sequence, that specifies which of the 20 amino acids will be added to the protein during translation. imagine that a prokaryote-like organism has been discovered in the polar ice on mars. interestingly, these martian organisms use the same dna → rna → protein system as life on earth, except thatthere are only 2 bases (a and t) in the martian dna, andthere are only 17 amino acids found in martian proteins. based on this information, what is the minimum size of a codon for these hypothetical martian life-forms?

The right answer is 5.

To answer this question, we must think in the same way as the demonstration showing that codons of 3 are necessary to encode an amino acid (in terrestrial species).

To calculate the number of nucleotides in a codon in these new species: we should use the law of:

nucleotides existing ^ (number of nucleotides in a codon) = number of codons.  (in order to have the number of possible codon combinations)

The number of codons must be greater than or equal to the number of amino acids (17).

2 ^ 1 = 2 (<17)

2 ^ 2 = 4 (<17)

2 ^ 3 = 8 (<17)

2 ^ 4 = 16 (<17)

2 ^ 5 = 32  (> 17)

32> 17 so the number of nulceotides in a codon must be 5.

photosynthesis makes the glucose that is used in cellular respiration to make atp. the glucose is then turned back into carbon dioxide, which is used in photosynthesis. while water is broken down to form oxygen during photosynthesis, in cellular respiration oxygen is combined with hydrogen to form water.

if you add everything up correctly you should get 69 i got this because 50 plus 19 is it