In a population with two alleles, b and b, the allele frequency of b is 0.8. what would be the frequency of heterozygotes of the population is in hardy weinberg equilibrium?

explain everything and all of the math

0.32

Explanation:

We will use the following equations;

p + q = 1

p2 + 2pq + q2 = 1

Therefore;

If B = 0.8; then b = 1 – 0.8 = 0.2

Heterozygous population is represented by 2pq; 2 * 0.8 * 0.2 = 0.32

i think that the best answer would be c.

tell me if im wrong : )