In cows, long hair is dominant to short hair. in a cow that is heterozygous for long hair, what percentage of the cells undergoing meiosis will carry the dominant allele?

Given –

Organism under consideration - cow

Character – size of the hair

Dominant trait – long hair

Recessive trait – short hair

Genotype – heterozygous dominant

Solution –  

Let the dominant trait be represented by L

Let the recessive trait be represented by l

In heterozygous condition the parent cow will have alleles as – Ll (male), Ll (female)

Cross between male and female would result in  

Ll

LLLLl

lLlll

Phenotype of the offspring – 75% with long hair, 25% with short hair

Genotype of the offspring – Homozygous dominant – 25%

                                               Heterozygous dominant – 50%

                                               Recessive dominant – 25%

Therefore, offspring's with dominant allele is 75% (25+ 50)

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.