What two types of amino acid sequences are needed in a protein to mediate post-translational farnesylation?

Post translation farnesylation may be defined as a type of prenylation in which the isoprenyl group is added to the cysteine residues of the protein. This modification is important for protein and membrane interaction.

Basically two types of amino acid are required for the farsenylation modification. The signal peptide sequence is the short amino acid sequence that targets the ribosome in the endoplasmic reticulum. The sequence is generally lysine, aspartic acid, glutamic acid and leucine. The second sequence must be Caax (C is cysteine, a is aliphatic amino acid and X consists of C terminal amino acid.

climate change and pollution

an individual’s sex (i.e., whether they are a male or female) is determined by the sex chromosomes. most people have two sex chromosomes, one that is inherited from their mother and one that is inherited from their father. typically, females have two x chromosomes (xx) and males have one x chromosome and one y chromosome (xy). conditions caused by changes (“mutations”) in genes located on the x chromosome are considered x-linked.

x-linked recessive inheritance

most x-linked conditions are recessive. this means that in a person with two x chromosomes (most females), both copies of a gene (i.e., one on each x chromosome) must have a change or mutation whereas in a person with one x chromosome (most males), only one copy of a gene must have a mutation. a female with a mutation in one copy of a gene on the x chromosome is said to be a “carrier” for an x-linked condition. a male with a mutation in a gene on the x chromosome is typically affected with the condition. because females have two copies of the x chromosome and males have only one x chromosome, x-linked recessive diseases are more common among males than females. however, x-linked recessive diseases can occur in both males and females.

for x-linked recessive disorders, an unaffected carrier mother who has a mutation in a gene on the x chromosome can transmit either the x chromosome with this mutation or a “normal” x chromosome to her children. if the father is unaffected, none of her daughters will be affected and all of her daughters will be unaffected—since they will inherit at least one normal x chromosome from their father. however, each daughter will have a 50% chance of being an unaffected carrier like her mother and a 50% chance of both x chromosomes being normal.