During a pulse-chase experiment, photographic emulsions were prepared at different times during the chase, and radioactive spots were detected at the following times and locations: 5 minutes: rough er; 10 minutes: golgi apparatus; 40 minutes: endosomes; 70 minutes: lysosomes; 140 minutes: lysosomes. which of the following conclusions can be drawn from these results

Pulse chase experiment was performed to find the secretory pathway of proteins inside the cell. The protein sorting and pathway of protein can easily be studied by the pulse chase experiment.

The molecule is labelled with radioactive component and its pathway is observed during the pulse chase experiment. The molecule reside  5 minutes in rough ER. After this 40 minutes in glogi apparatus. From the golgi apparatus the molecules moves towards the endosomes and resides for 70 minutes. The molecules then transferred to lysosomes in 140 minutes. This chasing explains the pathway of the molecule.

The pathway can be drawn is ER→golgi→endosome→lysosome.

answer-

the statement that f(x) = |x+a| + b has exactly one x-intercept is sometimes correct.

solution-

it solely depends on b, whether the function will have one or two or zero x intercept.

this plot of the given function, f(x) = |x+a| + b will be the basic absolute value graph i.e v shape, with vertex translated to (-a, b), instead of origin.

1-   if b is zero, the graph will have exactly one x-intercept, at x= -a

2- if b is positive, the whole graph will be above the x-axis, hence it will have no x-intercepts.

3- if b is negative, the graph will be below the x-axis, hence it will have two x-intercepts.

∴ the statement is sometimes true.