Transcribe the mrna sequence (a t g c g c a t t a g t g c a g g a c a g t a g) into a protein using the codon chat below. write your answer in the following format: - -

DNA      ATG  CGC ATT AGT GCA  GGA CAG TAG

mRNA   UAC  GCG UAA UCA CGU CCU GUC AUC

tRNA     AUG  CGC AUU AGU GCA GGA CAG UAG

Protein Met  Arg    Ile    Ser    Ala   Gly   Gin   Stop    

Explanation:

The given is a DNA sequence. The next step to this one is transcribing it into a mRNA sequence. When you transcribe DNA to RNA, the main difference between RNA and DNA is that RNA does not have a THYMINE (T) base. So what do we do?

The base pairs would be:

G - C        T - A

C -G         A - U

                U - A

So keep this in mind. Let's take the first one codon (codon is a group of 3 bases):

A T G        

U A C

A transcribes to U

T transcribes to A

G transcibes to C

So that would be your first codon.

The next part wi=ould be translation. Now in translation, a specific amino acid codes for a specific codon. They are brought by tRNA, which has a anti-codon that codes for the amino acid it carries.

Let's take that same codon we transcribed earlier:

ATG

UAC

AUG

Looking at the chart, first look at the first letter, then match it up with the row it corresponds to.

So it falls under A, so look at the row of A.

The next step is to look at the column the second letter corresponds to, following the same row you started in.

Last would be the row within the column you identified that corresponds to the third letter of the codon.

As you can see you wil end up in the box:

AUU

AUC

AUA

AUG

The higlighted sequence is the codon we are examining and based on the box, you can see that it is the Met. So this would be your first amino acid, and this is also known as the start codon by the way.

gametes or germ cells are haploid cells (example: sperm and ova) containing only one set (or n) number of chromosomes and autosomal or somatic cells are diploid cells containing 2n number of chromosomes.