In humans, red blood cells have a number of proteins embedded in the cell membrane. one type of protein, the rh factor, is controlled by a single gene and is either present or missing from the red blood cells. if present, the individual has the rh+ phenotype. of missing, the individual has the rh− phenotype. rh+ is the dominant to rh−. suppose that, in the welsh population, the frequency of the rh− phenotype is 0.04. using the hardy–weinberg equations, calculate the frequency of the rh allele to at least two decimal places.

Frequency of Rh-= 0.20

Frequency of Rh+ = 0.80

Explanation:

According to the given information, the allele Rh- is recessive to the allele Rh+. The given frequency of homozygous recessive genotype (Rh-Rh-) in the Welsh population is 0.04

Therefore, the frequency of homozygous recessive phenotype in the population (q^2)= 0.04

The frequency of recessive allele (Rh-)= square root of 0.04 = 0.20

Since the population is in Hardy–Weinberg equilibrium, p+q=1

Here, p= frequency of dominant allele

q = frequency of recessive allele

Since the frequency of a recessive allele (q)=0.2 0

So, frequency of dominant allele (p)= 1-0.2 = 0.8 0

i would say it is

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