The lac operon in e. coli controls the gene expression of the enzymes that digest lactose in the cell. in the absence of lactose, the lac operon will turn off and gene expression will be inactivated. place the events of gene regulation by the lac operon in order of their occurrence, from the removal of lactose from the environment to when the cell no longer digests lactose. not all the events will be placed.

a. the repressor is activated in the absence of lactose
b. the regulatory gene expressed the repressor protein
c. rna polymerase is prevented from binding the promotor
d. the repressor binds to the operator
e. lactose enzymes genes are inactivated by the operon

b, a, d, c, e

Explanation:

The lac operon is called lactose operon is a cluster of genes with a promoter. The bacteria uses lactose as the source of energy by the proteins coded by genes. This is present in prokaryotes.

The regulatory gene codes for repressor protein. The repressor binds to lactose and prevent its binding to operator. In the absence of lactose repressor gets activated and binds with operator. Thus, RNA polymerase is prevented from binding the promotor. The transcription of genes inhibited. Thus correct order is b, a, d, c, e.

the answer would be 2, if crossing over doesn’t occur 2 out of 4 of the daughter cells will have that allele.

hope this : )

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