Wild-type strains of e. coli have a trna with a 5′-gua-3′ anticodon that recognizes the uac codon for tyrosine. we can represent this trna as gua-trnatyr. suppose you isolated a strain of e. coli in which a mutation changed the anticodon in this trna to 5′-cua-3′ (creating cua-trnatyr). answer the following questions about translation elongation in each strain. for each answer, type in "yes" or "no".
a. will the wildtype trna recognize a normal uac codon in the a site?
b. will the mutant trna recognize a normal uac codon in the a site?
c. will the wildtype trna recognize a stop codon in the a site?
d. will the mutant trna recognize a stop codon in the a site?
e. will peptide bond formation occur with the wildtype trna bound in the a site?
f. will peptide bond formation occur with the mutant trna bound in the a site?
g. will the normal, wildtype protein be produced in the wildtype strain?
h. will the normal, wildtype protein be produced in the mutant strain?

The anticodon of the mutant tRNA that is CUA will recognize UAG which is a termination codon or nonsense codon or stop codon.

Explanation:

A   yes

B   no

C  no

D  yes

E   yes

F  no

G   yes

H    no

In the mutant strain the tRNA recognizes a stop codon UAG  for this reason protein synthesis will terminate at the stop codon.

oxidation

explanation:

answer

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.