For this question, we will utilize a population of martians that is in hardy weinberg equilibrium. the dominant martian phenotype is the possession of 2 antennae. in this population, 84 of the martians have 2 antennae, while 16 lack antennae. what is the frequency of heterozygotes in this population?
a. o.16
b.0.4
c.0.6
d.0.24
d.0.48

d.0.48

Explanation:

When a population is in Hardy Weinberg equilibrium the genotypic frequencies are:

freq (AA) = p²

freq (Aa) = 2pq

freq (aa) = q²

p is the frequency of the dominant A allele and q is the frequency of the recessive a allele.

In this population of 100 individuals, 84 martians have the dominant phenotype and 16 have the recessive phenotype.

Therefore:

q²=16/100

q² = 0.16

q=√0.16

q = 0.4

And p+q=1, so:

p = 1 - q

p = 1-0.4

p = 0.6

The frequency of heterozygotes is:

freq (Aa) = 2pq = 2 × 0.4 × 0.6

freq (Aa) = 0.48

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explanation:

plate tectonics and volcanic euptions

over time, plate tectonic processes cause continents to move to different positions on the globe.

for example, britain was near to the equator 300 million years ago, and therefore was hotter than it is today. for further details look at our climate through time poster or online map.

the movement of the plates also causes volcanoes and mountains to form and these too can contribute to a change in climate.

mountain ranges formed by plate tectonics. large mountain chains can influence the circulation of air around the globe, and consequently influence the climate.   warm air might be deflected somewhere cooler by the mountains.