An enzyme has a maximum velocity of 48 nmoles substrate converted per sec. in the presence of 4 um inhibitor, vmax is 36 nmoles substrate converted per sec with no change in km. determine the ki of the inhibitor. identify the type of inhibitor with explanation.

this might

answer; ///stratum basale///stratum spinosumstratum granulosumstratum lucidumstratum corneum; 2,1,5,4,3

during expiration the diaphragm relaxes, which causes the diaphragm to move downwards. the contraction of diaphragm increases the space for expansion of lungs. hence, the diaphragm relaxes and positioned downward during expiration.