In garden peas, the allele for tall plants is dominant over the allele for short plants. a true-breeding tall plant is crossed with a short plant, and one of their offspring is test crossed. out of 20 offspring resulting from the test cross, about how many should be tall?
a. 5
b. 20
c. 10
d. 0
e. 1/2

Option C

Out of the 20 resulting offspring of the test cross, 10 (50%) will be tall.

Explanation:

Let True-breeding tall plant be "TT"

Let short plant be tt

On crossing, all offspring will be "Tt"

Test cross involves the breeding of an individual with a phenotypically recessive individual. The test cross of offspring "Tt" against "tt" will then yield an equal ratio (1:1) of Tt to tt.

Thus, out of the 20 resulting offspring of the test cross, only 10 (50%) will be tall.

i think that is new experiments yield untrustworthy data and should be carefully considered, because you don't know what will happen with the experiments.

it has to be understood that the sea water contains a huge amount of sodium and chlorine ions and if they enter the cell of the atlantic cod fish, the cell will shrivel and the fish will die. to avoid such a condition, the fish uses active transport for the purpose of removing the ions against the gradient.

explanation:

the atlantic cod is not a maritime osmoconformer. its native application of salts is less than that of the seawater it lives in. it is continually falling water from the gills to the ocean via osmosis.

countering that, the fish is going to be swallowing seawater. but since its internal collection of salts is lower than seawater, the fish will want to go free of excess salt, and since that's going upon a gradient, then active transport, requiring energy, must be used to pump out the salt. much marine fish use the organs to filter out the salt and these fish discharge very straight urine.