If an individual homozygous dominant for widow's peak has a child with an individual heterozygous for widow's peak, what is the chance that the child will have a widow's peak?

100%

Explanation:

Let PP represent homozygous dominant trait for widow's peak &

Let Pp represent  an individual heterozygous for widow's peak.

If both traits cross together;  the chance that the child will have a widow's peak = ???

i.e PP × Pp

   |     P     |     P

P  |    PP   |     PP        

p  |    Pp   |     Pp

The progeny are: ( PP, PP, Pp, Pp)    

When a trait is dominant, only one allele is required for the trait to be observed. A dominant allele will mask a recessive allele, if present.

From our question, one  parent is homozygous dominant (PP) and the other is  heterozygous (Pp):  therefore  all their offspring will be  two homozygous dominant (PP) and two heterozygous  (Pp) and they will all possess a widow’s peak.

Therefore, the chance that a child will have a widow's peak = 100%

sexual reproduction produces offspring with novel combinations of genes. species that reproduce sexually must maintain two different types of individuals, males and females, which can limit the ability to colonize new habitats as both sexes must be present.

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