You are interested in two traits in rabbits, each of which is controlled by a separate gene with two alleles:

a) coat color (brown, b, is completely dominant to white,

b) and tail (tailed, t, is completely dominant to tail-less,

c) you cross a brown, tailed rabbit that is heterozygous at both loci with a white, tail-less rabbit and produce a large number of offspring.

among the offspring you find only two phenotypes in equal proportions: brown, tailed and white, tail-less.

the scenario here with the brown tailed rabbit RrTt

The white tailess rabbit is rt.

Crossing both yields the below offsprings possibilities;

For colour: Rr or rr

For tail: Tt or tt

That means they would produce equal numbers of Brown tailed & white tailess rabbits.

Explanation:

1. dermis

2. chemical

3. urine

4. viruses

5. antibodies

answer: glucoamylase presented optimum activity at temperature of 55â°c, and, in the glycosidic bonds from the non-reducing ends of starch, resulting in the production of glucose. source and type of fermentation can affect the enzyme's properties

credit to kalahira