Consider a cross between individuals that are: aabbccdd and aabbccdd in which all genes segregate independently. what frequency of progeny will have the same genotype as the aabbccdd parent?

1/16

Explanation:

The genotype of parents: AaBbCcDd and AAbbccDD

To calculate the frequency of a child with a specific genotype, we can calculate the individual frequencies for each gene and apply the product rule to calculate the overall frequency.

Aa x AA = 1/2 Aa: 1/2 AA

Bb x bb = 1/2 Bb: 1/2 bb

Cc x cc = 1/2 Cc: 1/2 cc

Dd x DD= 1/2 DD: 1/2 Dd

Therefore, the frequency of a progeny with genotype AAbbccDD = 1/2 AA x 1/2 bb x 1/2 cc x 1/2 DD = 1/2 x 1/2 x 1/2 x 1/2 = 1/16 or 0.0625 .

cellular respiration oxidizes food into energy in the form of atps.

glycolysis (6 c hexose) > 2x atps are used > 6c hexose biphosphate > 2 x 3c triphosphate >

2 x 3c pyruvate (2x nadh produced from nad) and (4x atp produced)

pyruvate actively pumped mitochondrial matrix.

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