If the frequency of an allele is 0.75, how many copies of this allele should be in a population of 300 diploid individuals?

I have provided the options below:

a. 150

b. 225

c. 300

d. 450

e. 75

150

Explanation:

Hardy-Weinberg law states, the allelic frequencies of a gene that is, q and p follow the relationship p^2+q^2+2pq = 1, if the population is in equilibrium.

Therefore p^2+q^2+2pq = 1, can be used to calculate the percentage of the allelic frequencies i.e. p^2 and q^2

Allelic frequency = 0.75.

Therefore, the percentage of the allele in the population would be given by

0.75^2 = 0.5625 = 56%.

And the total number of individuals with this allele in the population:

number of individuals = 56×300÷100

= 168 or

150 nearest figure.

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