If a female drosophila that is heterozygous for a recessive x-linked mutation is crossed to a wild-type male, what proportion of female progeny will have the mutant phenotype?

0% (none)

Explanation:

The female drosophila is heterozygous for X-linked recessive mutation. An X-linked recessive mutation is expressed in females only when present in the homozygous state. Therefore, the female progeny should have two copies of the mutant allele to express this mutation. Let's suppose that the genotype of the heterozygous female is X^cX and that of the male is XY. The cross would obtain progeny in following ratio=

X^cX x XY= 1/4 X^cX: 1/4 XX: 1/4 X^cY: 1/4 XY

Since none of the female progeny is homozygous recessive (X^cX^c), the cross would not obtain any female progeny expressing the X-linked recessive mutation.

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