What will be the theoretcal yield of tungsten(s) ,w, if 45.0 g of wo3 combines as completely as possible with 1.50 g of h2? wo3(s) + 3h2(g) => w(s) + 3 h2o(g).

Theoretical yield of tungsten produced = 35.6836915592  ≈ 35. 68 g

Explanation:

The chemical equation can be expressed as follows;

WO3 (s) + 3H2(g) → W(s) + 3 H20(g)

Note that the equation is already balanced.

Molecular Mass of WO3= 183.84 + 15.999 × 3 = 183.84 + 47.997  = 231.837 g

From the equation 1 mole of WO3 reacts with 3 mole of hydrogen molecule.

Molecular mass of tungsten(W) = 183.84 g

1 mole of tungsten was produced from the chemical equation.

WO3 (s) + 3H2(g) → W(s) + 3 H20(g)

From the equation,

231. 837 g of WO3 produces 183.84 g of tungsten

45.0 g of WO3 will produce ?

grams of tungsten produced = 183.84 × 45 /231.837

grams of tungsten produced = 8272.8 /231.837

Theoretical yield of tungsten produced = 35.6836915592  ≈ 35. 68 g

one part of the electromagnetic spectrum that arrives on earth as solar radiation from the sun is the visible spectrum. wavelengths of the visible spectrum combine to form what we refer to as

answer - d) ultraviolet radiation.

violet /   380–450 nm / 668–789 thz

violet is number 1 in the chart of visible light.