In a certain population of rabbits, the allele for brown fur is dominant over the
allele for white fur. if 10 out of 100 rabbits have white fur, what is the allele
frequency for the dominant allele?
the hardy-weinberg equation is:
[homozygous dominant]2 + 2[heterozygous] + [homozygous recessive]2 = 1
o a. 0.95
o b. 0.90
o c. 0.68
o d. 0.10

The allele  frequency for the dominant allele is 0.68.

C. 0.68

Explanation:

Let,

The Brown dominant allele be BB

The white recessive allele be bb

Frequency of white fur rabbit (bb) = 10/100 = 0.1

Therefore, q2 = 0.1

Frequency of recessive allele, q= √0.1

                                                  q = 0.316

Using Hardy Weinberg equation:

p+q = 1

p = 1-q

p = 1-0.316

p = 0.684

Thus, frequency of dominant allele, p = 0.684

affects the water bodies: excessive use of fertilizers causes eutrophication. the fertilizers which are used on plants affect the quality of land on which it is used, further causing erosion of soil. the fertilizers used on plants contain harmful chemical fumes which affect the environment.

acceleration = 18/3 = 6 m/s per second.

hope i

-lavira: )