Ahomozygous type b woman marries a heterozygous type a man. show punnett square genotypes and phenotype

Phenotype is Type A: Type B

Genotype is 1:1

Explanation:

It is given that type B woman is homozygous.  

Thus the genotype of the woman can be BB or bb

The man is of type A and heterozygous.

Thus the genotype of the man is Bb

We see that when the genotype is heterozygous Bb then the gene expresses type A condition

So, when the alleles are in homozygous dominant condition then the gene BB will also express in type A condition.

But we know that the women is type B. So, the genotype of the women is bb.

Cross between bb X Bb is shown in the punnett square attached

Thus,

Phenotype is Type A: Type B

Genotype is 1:1

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.