What is the genotypic and phenotypic ratio of a homozygous dominant and recessive cross

The genotypic ratio of a homozygous dominant and homozygous recessive cross is four heterozygous dominant is to zero, (4:0 = 4) that is, all the offsprings will be heterozygous dominant.

The phenotypic ratio is four outwardly dominant offsprings.

Explanation:

For instance, if T represents the dominant gene for tall heightwhile t represents the recessive gene for shortness height and a man who is homozygous tall TT mates a woman who is homozygous short (tt), the genotype of all their children will be heterozygous tall (Tt) and they will manifest phenotypically as tall because the gene for tall height (T) is dominant over the gene for short height (t).

See the punnett square attached

answer: c. two haploid cells

explanation:

answer: blah

explanation:

bc blah