For a project, a student is required to produce a sound with a frequency of 440 Hz or the equivalent of an A note. If the speed of the sound wave is 345 m/s, what wavelength must the wave be? What formula did you use to find this out? What would you need to do to the wavelength to produce a higher frequency?

The wave must be of wavelength of 0.78 m.

To obtain higher frequency the wave length would be shorten.

Explanation:

from the formula

v= fλ

v= velocity

f= frequency

λ= wavelength

Data given

f= 440Hz

v= 345m/sec

λ= v/f

  = 345 m/sec/ 440

   = 0.78 m

the wave must be of wavelength of 0.78 m.

If higher frequency is required wavelength would be shorten because from the formula wavelength is inversely proportional to frequency.

a=c and then d= c because of the band so you get ac/dc and you add them together you get sound waves