A species of fly has two alleles for the length of their legs. The allele for long
legs is dominant, and is represented by p. The allele for short legs is
recessive, and is represented by q. If 12 of 100 organisms have short legs,
what is p?
p+ 2pq+q=1
O A. 0.35
OB. 0.98
O C. 0.12
O D. 0.65

According to Hardy Weinberg law (p+q)2=1 where p is fequency of one allele and q is the frequency of another allele.

According the question

 q represent the short legs and 33 of 100 organism have short legs.

   As a result the frequency of q with respect to the 100 organism is 33/100

                                                                                                                  =0.33

Therefore q=0.33

 we all know that

            (p+q)2=1

             ∴  p+q= 1

             ∴  p=1-q

               p= 1-0.33

                   p=0.67

The frequency of p is 0.67

Explanation:

i'm gonna put a couple so you can chose from

explanation:

if you know the fur color of the offspring mice, you can use the ratios to identify the genotypes of the parents.

if either parent mouse passes a dominant allele, the offspring will have black fur.

if the parental mice has two different fur color (i.e white and black) , the color of the offspring's fur would be either black, white, or the combination of both (grey)

hope this : )

the offspring would all be white. if the parents are both white flowers then they have the genotype rr, which when crossed results in an all white punnet square.