The correct answer is 0.038 but I need detailed steps how to get there. Thanks!

HI decomposes to H2 and I2 by the following equation:

2HI(g) → H2(g) + I2(g);Kc = 1.6 × 10−3 at 25∘C

If 1.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C, what is the equilibrium concentration of H2 (g)?

a. 0.924 M
b. 0.076 M
c. 0.038 M
d. 0.0017 M

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ask your friends for what they got then copy it down if you don't have any friends which is fine than google it or pay the teacher

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