What is the expected Hardy-Weinberg frequency of heterozygotes in a population of green anoles, where the locus under investigation has two alleles and the frequency of one allele is 0.005 (give your answer to five decimal places)

0.00995

Explanation: The Hardy-Weinberg

theorem states that:

1. allele frequencies in a population will not change from generation to generation.

2. if the allele frequencies in a population with two alleles at a locus are p and q, then the expected genotype frequencies are P², 2pq, and q². For a population in genetic equilibrium:

p + q = 1.0

Where

p = the frequency of the dominant allele

q = the frequency of the recessive allele

Therefore

p² + 2pq + q² = 1

Where

p² = frequency of AA (homozygous dominant)

2pq = frequency of Aa (heterozygous)

q² = frequency of aa (homozygous recessive)

To get the frequency of frequency of heterozygotes in a population of green anoles,

p + q = 1.0

P= 0.005

q= ?

Therefore

q= 1 - P

q= 1 - 0.005

q= 0.995.

Therefore, the frequency of heterozygotes in a population of green anoles is 2Pa

Where P = 0.005

q= 0.99

Frequency of heterozygotes is

2Pa= 2 x 0.005 x 0.995

= 0.00995(five decimal)

humans can cause extinction of a species through overharvesting, pollution, habitat destruction, introduction of invasive species (such as new predators and food competitors), overhunting, and other influences. explosive, unsustainable human population growth is an essential cause of the extinction crisis.

explanation:

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answer:

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