Newsweek in 1989 reported that 60% of young children have blood lead levels that could impair their neurological development. Assuming a random sample from the population of all school children at risk, find the probability that at least 5 children out of 10 in a sample taken from a school may have a blood level that may impair development.

The answer is 83.38%.

Explanation:

The probability of young children having blood levels that impair their neurological development is given as 60% in the question. To find the probability of at least 5 children out of 10 in a sample having said blood levels, we need to use the binomial probability.

n represents the total number of children in the sample so n = 10 and p is the probability of the children having blood levels causing the problem which is 60% so p = 0.6.

We want the probability of it being observed for 5 or more children and that is . If we subtract the from 1, which is the probability of not observing the condition in 5 or more children, we will have the .

which are the probability range in the function, the sample size and the probability of observing the condition respectively.

The result is 1 - 0.1662 = 0.8338 which means that the probability that is asked is 83.38%.

I hope this answer helps.  

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explanation:

c.) polymerase chain reaction

- "unlike the original dna fingerprinting method, dna profiling does not use restriction enzymes to cut the dna. instead it uses the polymerase chain reaction (pcr)? to produce many copies of specific str sequences. pcr is an automated procedure that generates lots of copies of a specific sequence of dna."