In the case of the competitive inhibitor, we said that both k1 and KM are altered by that inhibitor. Since an uncompetitive inhibitor alters KM, does that mean that an uncompetitive inhibitor changes the value of k1?

No changes occur to the K1 value, its concentration remains higher than the concentration of the inhibitor and enzyme inhibitor complex

Explanation:

Uncompetitive inhibition is an example of a reversible inhibition. Reversible inhibitors bind to enzymes by weak non-covalent bonding. Thus the formation and dissociation of this association is rapid. uncompetitve inhibition lowers the Vmax and Km.

the relative atomic mass of an element is the mass of one atom of that element, relative to 1/12th of the mass of a  1212c atom. to convert to an absolute mass in kg, it is necessary to multiply by  1.661×10−271.661×10−27.

the relative atomic mass is roughly equal to the number of neutrons, plus the number of protons, in the nucleus of the atom.

for elements with more than one stable isotope (different types of nucleus with different numbers of neutrons but the same number of protons), the quoted mass is usually the average mass, weighted by the relative abundance of the different isotopes.