A genetic study conducted over two generations found that the frequencies of genotypes in the first generation were AA: 0.36, Aa: 0.48, and aa: 0.16. In the second generation, genotype frequencies remained the same. According to the Hardy-Weinberg equilibrium, we can assume Group of answer choices the population is small and we cannot detect change. mating in this population is random. mutations have likely occurred, resulting in the same frequency. negative assortative mating has maintained gene frequencies.

mating in this population is random

Explanation:

According to Hardy-Weinberg equilibrium, allele frequencies in a population remain constant for generations in absence of evolutionary forces like genetic drift, natural selection, mutation etc. A population is in Hardy-Weinberg equilibrium if there is random mating ( not biased towards a particular phenotype ), no gene flow, large population size, no mutation and no selection. These factors are important as disturbing them will change the allele frequency. Hence, if this population is in Hardy-Weinberg equilibrium we can assume that mating in this population is random.

my teacher would say no s

if the hares very faster than they are now, and thus the lynx's hunting success rate drops because it will be harder to catch them, the rate that will change will be the pray-rate. the pray-rate will change because more hares will be able to survive, thus more individuals for reproduction, so the end result will be increasing population of hares.

the predator-rate will remain pretty much the same because there will be more than enough pray, but the hunting success rate is stagnant.