Pb(NO3)2+KI ——-> KNO3 + PbI2

This is a chemical equation that needs to be balanced,,, also the I’s are i's

The balance form of the equation is given below.

Pb(NO3)2+2KI ——-> 2KNO3 + PbI2

Explanation:

In this equation lead nitrate and potassium iodide are reactants while potassium nitrate and lead iodide are the products. In the unbalanced form of equation, two molecule of iodine are formed in the product whereas there is only one molecule of iodine is present in the reactant. So for balancing this, 2 value is put in front of potassium iodide but by putting 2, potassium is also double in the reactant so 2 is also placed in front of potassium nitrate in the product and the equation is balanced.

The balanced equation is Pb(NO3)2 + 2KI ——-> 2KNO3 + PbI2.

Explanation: In writing chemical equations, the law of conservation of mass which states that matter can neither be created nor be destroyed in an ordinary chemical reaction must be obeyed. This means that the total mass of the reactants must be equal to the total mass of the products formed.

Pb(NO3)2 + 2KI ——-> 2KNO3 + PbI2.

The number of atoms on both sides of the equation must equal in the above equation.

The number of Pb atom is 1 on both sides. The number of N atoms is 2 on both sides. The number of O atoms on both sides is 6, the number of K atoms on both sides is 2 while the number of I atoms is 2 on both sides.

Therefore, the equation is balanced.

its probably to later but whats the question