Tongue-curling in humans is a dominant genetic trait (T). Suppose a man who is heterozygous for tongue-curling marries a woman who is also heterozygous for this trait. Create a Punnett Square. What percentage of the offspring will be phenotypic tongue-curlers? and What is the genotypic ratio (different genotype possibility)

The percentage of the offspring will be phenotypic tongue-curlers is 75% and the genotypic ratio is 1TT : 2Tt : 1tt

Explanation: Since tongue-curling in humans is a dominant genetic trait (T), then non tongue-curling is recessive trait and is represented as (t).

A man and woman who are heterozygous for tongue-curling will have genotype Tt. A cross between two heterozygous individuals will produce four offsprings, Tt x Tt = TT, Tt, Tt and tt.

The genotype ratio is 1TT : 2Tt : 1tt.

Since (T) is dominant, genotypes TT and Tt will manifest phenotypically as tongue-curling, while tt will manifest phenotypically as non tongue-curling.

Since three out of four offsprings are phenotypic tongue-curlers, the percentage of the offspring that are tongue-curlers is 3/4 x 100 = 75%

See the attached punnet square for more information

yes it is weird but true

i think it’s c but i might be wrong. if i am let me know! have a good rest of your day as well!