In peas, the allele for yellow seeds (Y) is dominant to the allele for green seeds (y). What would be the genotype and phenotype ratios of offspring from a cross between Yy (heterozygous) and yy (homozygous recessive) individuals?

The correct answer is explained below:

Explanation:

The allele for yellow seeds is Y.The allele for green seeds is y.The yellow colour phenotype is dominant over the green color phenotype.The genotype of the parent who is heterozygous is : Yy.The gametes produced by the parent who is heterozygous are: Y and y.The genotype of the parent who is homozygous recessive is: yy.The gamete produced by the parent who is homozygous recessive is: y.Crossing the above parents we get the following offspring,

                                           Y                    y

                               y         Yy                  yy

               Phenotype      Yellow          Green

The genotype and the phenotype of the possible offspring is represent in the Punnett square above.The ratio of the genotype is Yy : yy = 1 : 1.The ratio of the phenotype is Yellow : Green = 1 : 1.