If you have a compartment divided by a membrane. There are 8 molecules of SUCROSE on one side of the membrane and 10 molecules of FRUCTOSE on the other side of the membrane. When will the solution reach equilibrium for FRUCTOSE?

When there are 5 molecules of fructose on each side of the membrane.

Explanation:

The solution will reach equilibrium fro fructose when there are 5 molecules of fructose on each side of the membrane.

A membranous system is said to be at equilibrium when there are equal concentration of a particular molecule on both sides of the membrane.

Hence, for a membranous system with 10 molecules of fructose on one side, an equilibrium can only be reached for fructose when there are 5 molecules on one side and the remaining 5 molecules on the other side.

they both go up but then go back down. they both end lower than they started. lastly, they both are competitive/the second on.

explanation:

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