An individual heterozygous for eye color, skin color, and number of eyes mates with an individual who is homozygous recessive for all three characters; what would be the expected phenotypic ratio of their offspring? [Hint: B = black eyes, b = orange eyes; G = green skin, g = white skin; C = two eyes, c = one eye]

A) 9 black eyes, green skin, two eyes : 3 black eyes, green skin, one eye : 3 black eyes, white skin, two eyes : 1black eyes, white skin, one eye : 9 orange eyes, green skin, two eyes : 3 orange eyes, green skin, one eye : 3orange eyes, white skin, twoeyes : 1 orange eyes, white skin, one eye

B) 1 black eyes, green skin, two eyes : 1 black eyes, green skin, one eye : 1 black eyes, white skin, two eyes : 1orange eyes, green skin, two eyes : 1 orange eyes, white skin, two eyes : 1 orange eyes, white skin, one eye

C) 9 black eyes, green skin, two eyes : 3 black eyes, green skin, one eye : 3 black eyes, white skin, two eyes : 1black eyes, white skin, one eye

D) 9 orange eyes, green skin, two eyes : 9 orange eyes, green skin, one eye : 9 orange eyes, white skin, two eyes :1 orange eyes, white skin, one eye

E) 1 black eyes, green skin, two eyes : 1 black eyes, green skin, one eye : 1 black eyes, white skin, two eyes : 1

B) 1 black eyes, green skin, two eyes : 1 black eyes, green skin, one eye : 1 black eyes, white skin, two eyes : 1 orange eyes, green skin, two eyes : 1 orange eyes, white skin, two eyes : 1 orange eyes, white skin, one eye

Explanation:

Parentals:                     BbGgCc  x  bbggcc

The punette square diagram of the cross of these two parents is attached.

B = black eyes, b = orange eyes;

G = green skin, g = white skin;

C = two eyes, c = one eye

Progeny with BbGgCc genotype → black eyes, green skin, two eyes = 8

Progeny with BbGgcc genotype → black eyes, green skin, one eye = 8

Progeny with BbggCc genotype → black eyes, white skin, two eyes = 8

Progeny with bbGgCc genotype → orange eyes, green skin, two eyes = 8

Progeny with Bbggcc genotype → black eyes, white skin, one eye = 8

Progeny with bbGgcc genotype → orange eyes, green skin, one eye = 8

Progeny with bbggCc genotype → orange eyes, white skin, two eyes = 8

Progeny with bbggcc genotype → orange eyes, white skin, one eye = 8

So, if we will see them in the form of ratio then each of the genotype will be in the ratio of 1 i.e. black eyes, green skin, two eyes: black eyes, green skin, one eye: black eyes, white skin, two eyes: orange eyes, green skin, two eyes: black eyes, white skin, one eye: orange eyes, green skin, one eye: orange eyes, white skin, two eyes : orange eyes, white skin, one eye = 1:1:1:1:1:1:1:1.

So, in view of above option B is most appropriate.

Note: In a trihybrid cross, a total of 64 progeny types may be produced.

slitherio is the original. its the best friend of all middle schoolers. the man you can count any time you have some free time. slitherio is the guy you hang with while you're in the computer lab suppose to be doing "research or whatever". slitherio isn't just a game but a friend.

wormaxio is just a fake trying to squeeze its way into the friend group. trying to pretend its cool and your best pal but how long has it really been there for you, really. it only wants you as friend to boost its social status. wormaxio is just annoying fake pleb. no offense

you and have a wonderful day

do yall know the answer?