An enzyme catalyzed reaction is run with the kcat=20/min and the Km=4uM. Use the enzyme concentration from question 1 above. A very strong inhibitor is added creating an alpha value of 10, which then reduces the Vo down to 240 nM/min. What was the substrate concentration? Give your answer as a 2 digit number in units of uM.
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An enzyme catalyzed reaction is run with the kcat=20/min and the Km=4uM. Use the enzyme concentratio...
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